1c. Because the two lines have different sample size (11 and 13), t – independent is the appropriate statistic to be use for comparism.
1. Statement of hypothesis
a. Null hypothesis; there is no real differences between the two cowpea lines in their reaction the bruchids i.e ( = 0)
b. Alternative hypothesis; there is indeed a real difference in the reaction of cowpea lines to bruchids, i.e
2. Pool the variances
3. standard error of difference
4. Observed difference =
Pooled variance ( ) =
= =5.3397
= =5.3397
1.7916
=0.05449
Since =1.7916 =2.074, then, the H0 hypothesis is accepted and therefore concluded that the two lines are similar in their resistance to the insect.
Q2. (i)
Trait = Stand count
MD Sq.dev
IT95K 1072-57 27.00 2.33 5.444444
27.00 2.33 5.444444
20.00 -4.67 21.77778
74.00 0.00 32.67
24.67
Variance. 16.33
Variance = = 32/2= 16.33
Standard deviation = = 4.04
Coefficient of variation = x 100 = x100= 16.38%
50%DFF
MD Sq.dev
IT95K 1072-57 51.00 2.67 7.111111
43.00 -5.33 28.44444
51.00 2.67 7.111111
145.00 0.00 42.67
48.33
var. 21.33
Variance = 21.33
Standard deviation= =4.618
CV = x 100 = 21.65%
Trait = Maturity
MD Sq.dev
IT95K 1072-57 80.00 0.67 0.444444
78.00 -1.33 1.777778
80.00 0.67 0.444444
238.00 0.00 2.67
79.33
var. 1.33
Variance = 1.33
Standard deviation= =1.153
CV = x 100 = 1.45%
Total seed
MD sqdev
IT95K 1072-57 500.00 -33.33 1111.111
700.00 166.67 27777.78
400.00 -133.33 17777.78
1600.00 0.00 46666.67
533.33
var. 23333.33
Variance = 1.33
Standard deviation= =152.75
CV = x 100 = 28.64%
Trait CV (%)
1. Stand count 16.38
2 50% DFF 21.65
3. Maturity 1.45
4. Total seed 28.64
Q2. (ii)
Plot size = 2 row x 0.75 m x 5 m =7.5 m2
Mean seed yield per plot for IT97K-499-35=700+500+900= 21,000/3 =7,000 seeds
Therefore
7.5 m2 7,000 seeds
1 m2 7000/7.5
10,000 m2 7000/7.5 x 10,000
= 9.33 Million seeds
Mean seed yield per plot for IT97K-491-7=400+450+300=11,000/3= 3,667 seeds
7.5 m2 3,667 seeds
1 m2 3,667/7.5
10,000 m2 3,667/7.5 x 10,000
= 4.8933 Million seeds
